Integrand size = 18, antiderivative size = 139 \[ \int \frac {(a+b x)^n}{x (c+d x)^2} \, dx=-\frac {d (a+b x)^{1+n}}{c (b c-a d) (c+d x)}+\frac {d (a d-b c (1-n)) (a+b x)^{1+n} \operatorname {Hypergeometric2F1}\left (1,1+n,2+n,-\frac {d (a+b x)}{b c-a d}\right )}{c^2 (b c-a d)^2 (1+n)}-\frac {(a+b x)^{1+n} \operatorname {Hypergeometric2F1}\left (1,1+n,2+n,1+\frac {b x}{a}\right )}{a c^2 (1+n)} \]
[Out]
Time = 0.06 (sec) , antiderivative size = 139, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {105, 162, 67, 70} \[ \int \frac {(a+b x)^n}{x (c+d x)^2} \, dx=\frac {d (a+b x)^{n+1} (a d-b c (1-n)) \operatorname {Hypergeometric2F1}\left (1,n+1,n+2,-\frac {d (a+b x)}{b c-a d}\right )}{c^2 (n+1) (b c-a d)^2}-\frac {(a+b x)^{n+1} \operatorname {Hypergeometric2F1}\left (1,n+1,n+2,\frac {b x}{a}+1\right )}{a c^2 (n+1)}-\frac {d (a+b x)^{n+1}}{c (c+d x) (b c-a d)} \]
[In]
[Out]
Rule 67
Rule 70
Rule 105
Rule 162
Rubi steps \begin{align*} \text {integral}& = -\frac {d (a+b x)^{1+n}}{c (b c-a d) (c+d x)}-\frac {\int \frac {(a+b x)^n (-b c+a d-b d n x)}{x (c+d x)} \, dx}{c (b c-a d)} \\ & = -\frac {d (a+b x)^{1+n}}{c (b c-a d) (c+d x)}+\frac {\int \frac {(a+b x)^n}{x} \, dx}{c^2}+\frac {(d (a d-b c (1-n))) \int \frac {(a+b x)^n}{c+d x} \, dx}{c^2 (b c-a d)} \\ & = -\frac {d (a+b x)^{1+n}}{c (b c-a d) (c+d x)}+\frac {d (a d-b c (1-n)) (a+b x)^{1+n} \, _2F_1\left (1,1+n;2+n;-\frac {d (a+b x)}{b c-a d}\right )}{c^2 (b c-a d)^2 (1+n)}-\frac {(a+b x)^{1+n} \, _2F_1\left (1,1+n;2+n;1+\frac {b x}{a}\right )}{a c^2 (1+n)} \\ \end{align*}
Time = 0.12 (sec) , antiderivative size = 111, normalized size of antiderivative = 0.80 \[ \int \frac {(a+b x)^n}{x (c+d x)^2} \, dx=\frac {(a+b x)^{1+n} \left (-\frac {\operatorname {Hypergeometric2F1}\left (1,1+n,2+n,\frac {a+b x}{a}\right )}{a+a n}+\frac {d \left (\frac {c (-b c+a d)}{c+d x}+\frac {(a d+b c (-1+n)) \operatorname {Hypergeometric2F1}\left (1,1+n,2+n,\frac {d (a+b x)}{-b c+a d}\right )}{1+n}\right )}{(b c-a d)^2}\right )}{c^2} \]
[In]
[Out]
\[\int \frac {\left (b x +a \right )^{n}}{x \left (d x +c \right )^{2}}d x\]
[In]
[Out]
\[ \int \frac {(a+b x)^n}{x (c+d x)^2} \, dx=\int { \frac {{\left (b x + a\right )}^{n}}{{\left (d x + c\right )}^{2} x} \,d x } \]
[In]
[Out]
\[ \int \frac {(a+b x)^n}{x (c+d x)^2} \, dx=\int \frac {\left (a + b x\right )^{n}}{x \left (c + d x\right )^{2}}\, dx \]
[In]
[Out]
\[ \int \frac {(a+b x)^n}{x (c+d x)^2} \, dx=\int { \frac {{\left (b x + a\right )}^{n}}{{\left (d x + c\right )}^{2} x} \,d x } \]
[In]
[Out]
\[ \int \frac {(a+b x)^n}{x (c+d x)^2} \, dx=\int { \frac {{\left (b x + a\right )}^{n}}{{\left (d x + c\right )}^{2} x} \,d x } \]
[In]
[Out]
Timed out. \[ \int \frac {(a+b x)^n}{x (c+d x)^2} \, dx=\int \frac {{\left (a+b\,x\right )}^n}{x\,{\left (c+d\,x\right )}^2} \,d x \]
[In]
[Out]